(5y^2-24y)4=0

Solution for (5y^2-24y)4=0 equation:

(5y^2-24y)4=0

We multiply parentheses

20y^2-96y=0

a = 20; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·20·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*20}=\frac{0}{40}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*20}=\frac{192}{40}
=4+4/5
$